Base | Representation |
---|---|
bin | 1001010101011001… |
… | …01111110010010001 |
3 | 110221020201110201020 |
4 | 10222230233302101 |
5 | 40230400343213 |
6 | 2145134230053 |
7 | 235120455651 |
oct | 45254576221 |
9 | 13836643636 |
10 | 5011340433 |
11 | 2141853270 |
12 | b7a355329 |
13 | 61b2cc5c8 |
14 | 3577b4361 |
15 | 1e4e46923 |
hex | 12ab2fc91 |
5011340433 has 32 divisors (see below), whose sum is σ = 7536758784. Its totient is φ = 2934360000.
The previous prime is 5011340423. The next prime is 5011340449. The reversal of 5011340433 is 3340431105.
It is a happy number.
It is not a de Polignac number, because 5011340433 - 210 = 5011339409 is a prime.
It is a super-2 number, since 2×50113404332 = 50227065870841254978, which contains 22 as substring.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (5011340423) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 672498 + ... + 679908.
It is an arithmetic number, because the mean of its divisors is an integer number (235523712).
Almost surely, 25011340433 is an apocalyptic number.
It is an amenable number.
5011340433 is a deficient number, since it is larger than the sum of its proper divisors (2525418351).
5011340433 is a wasteful number, since it uses less digits than its factorization.
5011340433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8117.
The product of its (nonzero) digits is 2160, while the sum is 24.
The square root of 5011340433 is about 70790.8216720219. The cubic root of 5011340433 is about 1711.2677616959.
Adding to 5011340433 its reverse (3340431105), we get a palindrome (8351771538).
The spelling of 5011340433 in words is "five billion, eleven million, three hundred forty thousand, four hundred thirty-three".
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