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50114354441 is a prime number
BaseRepresentation
bin101110101011000011…
…000101110100001001
311210100112222222102112
4232223003011310021
51310113233320231
635004444312105
73422610661424
oct565303056411
9153315888375
1050114354441
111a287279258
129867242635
13495866b088
1425d59ba9bb
15148493292b
hexbab0c5d09

50114354441 has 2 divisors, whose sum is σ = 50114354442. Its totient is φ = 50114354440.

The previous prime is 50114354431. The next prime is 50114354447. The reversal of 50114354441 is 14445341105.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 33960961225 + 16153393216 = 184285^2 + 127096^2 .

It is a cyclic number.

It is not a de Polignac number, because 50114354441 - 230 = 49040612617 is a prime.

It is a super-2 number, since 2×501143544412 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 50114354398 and 50114354407.

It is not a weakly prime, because it can be changed into another prime (50114354447) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25057177220 + 25057177221.

It is an arithmetic number, because the mean of its divisors is an integer number (25057177221).

Almost surely, 250114354441 is an apocalyptic number.

It is an amenable number.

50114354441 is a deficient number, since it is larger than the sum of its proper divisors (1).

50114354441 is an equidigital number, since it uses as much as digits as its factorization.

50114354441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 19200, while the sum is 32.

Adding to 50114354441 its reverse (14445341105), we get a palindrome (64559695546).

The spelling of 50114354441 in words is "fifty billion, one hundred fourteen million, three hundred fifty-four thousand, four hundred forty-one".