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5011627433 is a prime number
BaseRepresentation
bin1001010101011011…
…10101110110101001
3110221021021001101212
410222231311312221
540230434034213
62145144322505
7235123062461
oct45255656651
913837231355
105011627433
112141a2995a
12b7a473435
1361b3a0127
1435784aba1
151e4ea19a8
hex12ab75da9

5011627433 has 2 divisors, whose sum is σ = 5011627434. Its totient is φ = 5011627432.

The previous prime is 5011627409. The next prime is 5011627451. The reversal of 5011627433 is 3347261105.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4803460249 + 208167184 = 69307^2 + 14428^2 .

It is a cyclic number.

It is not a de Polignac number, because 5011627433 - 222 = 5007433129 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 5011627433.

It is not a weakly prime, because it can be changed into another prime (5011627483) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2505813716 + 2505813717.

It is an arithmetic number, because the mean of its divisors is an integer number (2505813717).

Almost surely, 25011627433 is an apocalyptic number.

It is an amenable number.

5011627433 is a deficient number, since it is larger than the sum of its proper divisors (1).

5011627433 is an equidigital number, since it uses as much as digits as its factorization.

5011627433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15120, while the sum is 32.

The square root of 5011627433 is about 70792.8487419457. The cubic root of 5011627433 is about 1711.3004292346.

Adding to 5011627433 its reverse (3347261105), we get a palindrome (8358888538).

The spelling of 5011627433 in words is "five billion, eleven million, six hundred twenty-seven thousand, four hundred thirty-three".