Search a number
-
+
50120043593 is a prime number
BaseRepresentation
bin101110101011011000…
…110010110001001001
311210100221201000110212
4232223120302301021
51310121212343333
635005210250505
73423010225034
oct565330626111
9153327630425
1050120043593
111a28a504634
129869126a35
1349598b0739
1425d665c01b
1514851a8448
hexbab632c49

50120043593 has 2 divisors, whose sum is σ = 50120043594. Its totient is φ = 50120043592.

The previous prime is 50120043583. The next prime is 50120043641. The reversal of 50120043593 is 39534002105.

50120043593 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 35642419264 + 14477624329 = 188792^2 + 120323^2 .

It is a cyclic number.

It is not a de Polignac number, because 50120043593 - 24 = 50120043577 is a prime.

It is not a weakly prime, because it can be changed into another prime (50120043503) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25060021796 + 25060021797.

It is an arithmetic number, because the mean of its divisors is an integer number (25060021797).

Almost surely, 250120043593 is an apocalyptic number.

It is an amenable number.

50120043593 is a deficient number, since it is larger than the sum of its proper divisors (1).

50120043593 is an equidigital number, since it uses as much as digits as its factorization.

50120043593 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16200, while the sum is 32.

Adding to 50120043593 its reverse (39534002105), we get a palindrome (89654045698).

The spelling of 50120043593 in words is "fifty billion, one hundred twenty million, forty-three thousand, five hundred ninety-three".