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5012113 is a prime number
BaseRepresentation
bin10011000111101010010001
3100102122022211
4103013222101
52240341423
6255232121
760413401
oct23075221
910378284
105012113
112913747
121818641
131066462
14946801
1569010d
hex4c7a91

5012113 has 2 divisors, whose sum is σ = 5012114. Its totient is φ = 5012112.

The previous prime is 5012101. The next prime is 5012129. The reversal of 5012113 is 3112105.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4028049 + 984064 = 2007^2 + 992^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5012113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5012093 and 5012102.

It is not a weakly prime, because it can be changed into another prime (5012153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2506056 + 2506057.

It is an arithmetic number, because the mean of its divisors is an integer number (2506057).

Almost surely, 25012113 is an apocalyptic number.

It is an amenable number.

5012113 is a deficient number, since it is larger than the sum of its proper divisors (1).

5012113 is an equidigital number, since it uses as much as digits as its factorization.

5012113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 30, while the sum is 13.

The square root of 5012113 is about 2238.7748881922. The cubic root of 5012113 is about 171.1355695659.

Adding to 5012113 its reverse (3112105), we get a palindrome (8124218).

The spelling of 5012113 in words is "five million, twelve thousand, one hundred thirteen".