Base | Representation |
---|---|
bin | 101110101011011110… |
… | …100101000011111101 |
3 | 11210101001120002000211 |
4 | 232223132211003331 |
5 | 1310122104412232 |
6 | 35005302552421 |
7 | 3423026143003 |
oct | 565336450375 |
9 | 153331502024 |
10 | 50121560317 |
11 | 1a290350124 |
12 | 9869738711 |
13 | 4959cc1bca |
14 | 25d6934a73 |
15 | 14853a7a47 |
hex | bab7a50fd |
50121560317 has 2 divisors, whose sum is σ = 50121560318. Its totient is φ = 50121560316.
The previous prime is 50121560287. The next prime is 50121560429. The reversal of 50121560317 is 71306512105.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 34931983801 + 15189576516 = 186901^2 + 123246^2 .
It is a cyclic number.
It is not a de Polignac number, because 50121560317 - 231 = 47974076669 is a prime.
It is a super-2 number, since 2×501215603172 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (50121260317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25060780158 + 25060780159.
It is an arithmetic number, because the mean of its divisors is an integer number (25060780159).
Almost surely, 250121560317 is an apocalyptic number.
It is an amenable number.
50121560317 is a deficient number, since it is larger than the sum of its proper divisors (1).
50121560317 is an equidigital number, since it uses as much as digits as its factorization.
50121560317 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6300, while the sum is 31.
The spelling of 50121560317 in words is "fifty billion, one hundred twenty-one million, five hundred sixty thousand, three hundred seventeen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •