Base | Representation |
---|---|
bin | 100100011110010100100… |
… | …1101111000111110101011 |
3 | 122202020012220020212112112 |
4 | 1020330221031320332223 |
5 | 1124112424043412142 |
6 | 14354523005232535 |
7 | 1025112534565364 |
oct | 110745115707653 |
9 | 18666186225475 |
10 | 5012918341547 |
11 | 1662a6a798796 |
12 | 68b65426274b |
13 | 2a4940574a4c |
14 | 1348ab336b6b |
15 | 8a5e68e3382 |
hex | 48f29378fab |
5012918341547 has 2 divisors, whose sum is σ = 5012918341548. Its totient is φ = 5012918341546.
The previous prime is 5012918341523. The next prime is 5012918341549. The reversal of 5012918341547 is 7451438192105.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5012918341547 - 236 = 4944198864811 is a prime.
Together with 5012918341549, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 5012918341495 and 5012918341504.
It is not a weakly prime, because it can be changed into another prime (5012918341549) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2506459170773 + 2506459170774.
It is an arithmetic number, because the mean of its divisors is an integer number (2506459170774).
Almost surely, 25012918341547 is an apocalyptic number.
5012918341547 is a deficient number, since it is larger than the sum of its proper divisors (1).
5012918341547 is an equidigital number, since it uses as much as digits as its factorization.
5012918341547 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1209600, while the sum is 50.
The spelling of 5012918341547 in words is "five trillion, twelve billion, nine hundred eighteen million, three hundred forty-one thousand, five hundred forty-seven".
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