50134013 has 2 divisors, whose sum is σ = 50134014. Its totient is φ = 50134012.

The previous prime is 50133977. The next prime is 50134033. The reversal of 50134013 is 31043105.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 47706649 + 2427364 = 6907^2 + 1558^2 .

It is a cyclic number.

It is not a de Polignac number, because 50134013 - 2⁶ = 50133949 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 50133982 and 50134000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (50134033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25067006 + 25067007.

It is an arithmetic number, because the mean of its divisors is an integer number (25067007).

Almost surely, 2^50134013 is an apocalyptic number.

It is an amenable number.

50134013 is a deficient number, since it is larger than the sum of its proper divisors (1).

50134013 is an equidigital number, since it uses as much as digits as its factorization.

50134013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 180, while the sum is 17.

The square root of 50134013 is about 7080.5376208308. The cubic root of 50134013 is about 368.7319949841.

Adding to 50134013 its reverse (31043105), we get a palindrome (81177118).

The spelling of 50134013 in words is "fifty million, one hundred thirty-four thousand, thirteen".