Base | Representation |
---|---|
bin | 1001010101101101… |
… | …11000111100101001 |
3 | 110221102201120010112 |
4 | 10222312320330221 |
5 | 40232040440101 |
6 | 2145311224105 |
7 | 235152202025 |
oct | 45266707451 |
9 | 13842646115 |
10 | 5013999401 |
11 | 21432a9a64 |
12 | b7b218035 |
13 | 61ba20968 |
14 | 357ca7385 |
15 | 1e52be6bb |
hex | 12adb8f29 |
5013999401 has 2 divisors, whose sum is σ = 5013999402. Its totient is φ = 5013999400.
The previous prime is 5013999359. The next prime is 5013999443. The reversal of 5013999401 is 1049993105.
It is a balanced prime because it is at equal distance from previous prime (5013999359) and next prime (5013999443).
It can be written as a sum of positive squares in only one way, i.e., 4254170176 + 759829225 = 65224^2 + 27565^2 .
It is a cyclic number.
It is not a de Polignac number, because 5013999401 - 230 = 3940257577 is a prime.
It is not a weakly prime, because it can be changed into another prime (5013999451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2506999700 + 2506999701.
It is an arithmetic number, because the mean of its divisors is an integer number (2506999701).
Almost surely, 25013999401 is an apocalyptic number.
It is an amenable number.
5013999401 is a deficient number, since it is larger than the sum of its proper divisors (1).
5013999401 is an equidigital number, since it uses as much as digits as its factorization.
5013999401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 43740, while the sum is 41.
The square root of 5013999401 is about 70809.5996387495. The cubic root of 5013999401 is about 1711.5703688028.
The spelling of 5013999401 in words is "five billion, thirteen million, nine hundred ninety-nine thousand, four hundred one".
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