Base | Representation |
---|---|
bin | 1001010101110000… |
… | …01100001110001011 |
3 | 110221110100220000111 |
4 | 10222320030032023 |
5 | 40232132343431 |
6 | 2145322415151 |
7 | 235155122326 |
oct | 45270141613 |
9 | 13843326014 |
10 | 5014340491 |
11 | 2143512256 |
12 | b7b3614b7 |
13 | 61bb0cca4 |
14 | 357d557bd |
15 | 1e533a7b1 |
hex | 12ae0c38b |
5014340491 has 2 divisors, whose sum is σ = 5014340492. Its totient is φ = 5014340490.
The previous prime is 5014340449. The next prime is 5014340533. The reversal of 5014340491 is 1940434105.
It is a balanced prime because it is at equal distance from previous prime (5014340449) and next prime (5014340533).
It is a cyclic number.
It is not a de Polignac number, because 5014340491 - 223 = 5005951883 is a prime.
It is a super-2 number, since 2×50143404912 = 50287221119364242162, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5014340411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2507170245 + 2507170246.
It is an arithmetic number, because the mean of its divisors is an integer number (2507170246).
Almost surely, 25014340491 is an apocalyptic number.
5014340491 is a deficient number, since it is larger than the sum of its proper divisors (1).
5014340491 is an equidigital number, since it uses as much as digits as its factorization.
5014340491 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8640, while the sum is 31.
The square root of 5014340491 is about 70812.0080989093. The cubic root of 5014340491 is about 1711.6091792249.
Adding to 5014340491 its reverse (1940434105), we get a palindrome (6954774596).
The spelling of 5014340491 in words is "five billion, fourteen million, three hundred forty thousand, four hundred ninety-one".
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