Base | Representation |
---|---|
bin | 101110101100110100… |
… | …001010000001100101 |
3 | 11210102121202211012101 |
4 | 232230310022001211 |
5 | 1310143330301312 |
6 | 35011423452101 |
7 | 3423420626131 |
oct | 565464120145 |
9 | 153377684171 |
10 | 50143993957 |
11 | 1a2a1a82922 |
12 | 9875157031 |
13 | 4961847c55 |
14 | 25d98d43c1 |
15 | 1487339a57 |
hex | bacd0a065 |
50143993957 has 2 divisors, whose sum is σ = 50143993958. Its totient is φ = 50143993956.
The previous prime is 50143993891. The next prime is 50143993987. The reversal of 50143993957 is 75939934105.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 49554766881 + 589227076 = 222609^2 + 24274^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-50143993957 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 50143993898 and 50143993907.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (50143993987) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25071996978 + 25071996979.
It is an arithmetic number, because the mean of its divisors is an integer number (25071996979).
Almost surely, 250143993957 is an apocalyptic number.
It is an amenable number.
50143993957 is a deficient number, since it is larger than the sum of its proper divisors (1).
50143993957 is an equidigital number, since it uses as much as digits as its factorization.
50143993957 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4592700, while the sum is 55.
The spelling of 50143993957 in words is "fifty billion, one hundred forty-three million, nine hundred ninety-three thousand, nine hundred fifty-seven".
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