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5014512024131 is a prime number
BaseRepresentation
bin100100011111000100000…
…1101010011101001000011
3122202101022222001100001102
41020332020031103221003
51124124210034233011
614355345055325015
71025200165634321
oct110761015235103
918671288040042
105014512024131
111663708345035
1268ba19b2076b
132a4b357a81ac
141349bcc64d11
158a68b79573b
hex48f88353a43

5014512024131 has 2 divisors, whose sum is σ = 5014512024132. Its totient is φ = 5014512024130.

The previous prime is 5014512024103. The next prime is 5014512024209. The reversal of 5014512024131 is 1314202154105.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 5014512024131 - 210 = 5014512023107 is a prime.

It is a super-2 number, since 2×50145120241312 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5014512024094 and 5014512024103.

It is not a weakly prime, because it can be changed into another prime (5014512024331) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2507256012065 + 2507256012066.

It is an arithmetic number, because the mean of its divisors is an integer number (2507256012066).

Almost surely, 25014512024131 is an apocalyptic number.

5014512024131 is a deficient number, since it is larger than the sum of its proper divisors (1).

5014512024131 is an equidigital number, since it uses as much as digits as its factorization.

5014512024131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4800, while the sum is 29.

Adding to 5014512024131 its reverse (1314202154105), we get a palindrome (6328714178236).

The spelling of 5014512024131 in words is "five trillion, fourteen billion, five hundred twelve million, twenty-four thousand, one hundred thirty-one".