Base | Representation |
---|---|
bin | 101110101101010000… |
… | …000101011100010111 |
3 | 11210110010112210002101 |
4 | 232231100011130113 |
5 | 1310202214041343 |
6 | 35012244422531 |
7 | 3423540101002 |
oct | 565520053427 |
9 | 153403483071 |
10 | 50151315223 |
11 | 1a2a6123459 |
12 | 98776a7a47 |
13 | 496320c469 |
14 | 25da87c539 |
15 | 1487cd3e4d |
hex | bad405717 |
50151315223 has 2 divisors, whose sum is σ = 50151315224. Its totient is φ = 50151315222.
The previous prime is 50151315217. The next prime is 50151315299. The reversal of 50151315223 is 32251315105.
50151315223 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 50151315223 - 217 = 50151184151 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 50151315191 and 50151315200.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (50151315323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25075657611 + 25075657612.
It is an arithmetic number, because the mean of its divisors is an integer number (25075657612).
Almost surely, 250151315223 is an apocalyptic number.
50151315223 is a deficient number, since it is larger than the sum of its proper divisors (1).
50151315223 is an equidigital number, since it uses as much as digits as its factorization.
50151315223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4500, while the sum is 28.
The spelling of 50151315223 in words is "fifty billion, one hundred fifty-one million, three hundred fifteen thousand, two hundred twenty-three".
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