Base | Representation |
---|---|
bin | 100100011111011011111… |
… | …0001110110001111010101 |
3 | 122202110101120211102110211 |
4 | 1020332313301312033111 |
5 | 1124132323343212211 |
6 | 14400000205445421 |
7 | 1025226026511046 |
oct | 110766761661725 |
9 | 18673346742424 |
10 | 5015310132181 |
11 | 1663a87903468 |
12 | 690001270871 |
13 | 2a4c31c47b8b |
14 | 134a56c5a8cd |
15 | 8a6d6896e21 |
hex | 48fb7c763d5 |
5015310132181 has 2 divisors, whose sum is σ = 5015310132182. Its totient is φ = 5015310132180.
The previous prime is 5015310132163. The next prime is 5015310132223. The reversal of 5015310132181 is 1812310135105.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4965655140625 + 49654991556 = 2228375^2 + 222834^2 .
It is a cyclic number.
It is not a de Polignac number, because 5015310132181 - 217 = 5015310001109 is a prime.
It is a super-2 number, since 2×50153101321812 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5015310132881) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2507655066090 + 2507655066091.
It is an arithmetic number, because the mean of its divisors is an integer number (2507655066091).
Almost surely, 25015310132181 is an apocalyptic number.
It is an amenable number.
5015310132181 is a deficient number, since it is larger than the sum of its proper divisors (1).
5015310132181 is an equidigital number, since it uses as much as digits as its factorization.
5015310132181 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3600, while the sum is 31.
Adding to 5015310132181 its reverse (1812310135105), we get a palindrome (6827620267286).
The spelling of 5015310132181 in words is "five trillion, fifteen billion, three hundred ten million, one hundred thirty-two thousand, one hundred eighty-one".
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