Base | Representation |
---|---|
bin | 100100011111011011111… |
… | …0010100010001011000010 |
3 | 122202110101121011120022121 |
4 | 1020332313302202023002 |
5 | 1124132323414442010 |
6 | 14400000213354454 |
7 | 1025226031160506 |
oct | 110766762421302 |
9 | 18673347146277 |
10 | 5015310312130 |
11 | 1663a87a16688 |
12 | 690001338a2a |
13 | 2a4c31caba61 |
14 | 134a56ca6306 |
15 | 8a6d68d03da |
hex | 48fb7ca22c2 |
5015310312130 has 16 divisors (see below), whose sum is σ = 9027928332864. Its totient is φ = 2006041953520.
The previous prime is 5015310312121. The next prime is 5015310312149. The reversal of 5015310312130 is 312130135105.
It is a junction number, because it is equal to n+sod(n) for n = 5015310312095 and 5015310312104.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10014766 + ... + 10503625.
It is an arithmetic number, because the mean of its divisors is an integer number (564245520804).
Almost surely, 25015310312130 is an apocalyptic number.
5015310312130 is a deficient number, since it is larger than the sum of its proper divisors (4012618020734).
5015310312130 is a wasteful number, since it uses less digits than its factorization.
5015310312130 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 20542841.
The product of its (nonzero) digits is 1350, while the sum is 25.
Adding to 5015310312130 its reverse (312130135105), we get a palindrome (5327440447235).
The spelling of 5015310312130 in words is "five trillion, fifteen billion, three hundred ten million, three hundred twelve thousand, one hundred thirty".
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