Base | Representation |
---|---|
bin | 100100011111011111010… |
… | …0001100110011011000001 |
3 | 122202110200110210122012021 |
4 | 1020332332201212123001 |
5 | 1124133041332013401 |
6 | 14400015331401441 |
7 | 1025231602523041 |
oct | 110767641463301 |
9 | 18673613718167 |
10 | 5015423313601 |
11 | 1664035788328 |
12 | 690033153281 |
13 | 2a4c4c52532c |
14 | 134a67cbd721 |
15 | 8a6e17a22a1 |
hex | 48fbe8666c1 |
5015423313601 has 2 divisors, whose sum is σ = 5015423313602. Its totient is φ = 5015423313600.
The previous prime is 5015423313541. The next prime is 5015423313611. The reversal of 5015423313601 is 1063133245105.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3028800719025 + 1986622594576 = 1740345^2 + 1409476^2 .
It is a cyclic number.
It is not a de Polignac number, because 5015423313601 - 27 = 5015423313473 is a prime.
It is a super-2 number, since 2×50154233136012 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5015423313611) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2507711656800 + 2507711656801.
It is an arithmetic number, because the mean of its divisors is an integer number (2507711656801).
Almost surely, 25015423313601 is an apocalyptic number.
It is an amenable number.
5015423313601 is a deficient number, since it is larger than the sum of its proper divisors (1).
5015423313601 is an equidigital number, since it uses as much as digits as its factorization.
5015423313601 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 32400, while the sum is 34.
Adding to 5015423313601 its reverse (1063133245105), we get a palindrome (6078556558706).
The spelling of 5015423313601 in words is "five trillion, fifteen billion, four hundred twenty-three million, three hundred thirteen thousand, six hundred one".
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