Base | Representation |
---|---|
bin | 100100100000100011010… |
… | …1010111010001010101011 |
3 | 122202200120122211001100022 |
4 | 1021001012222322022223 |
5 | 1124202231102031042 |
6 | 14401034124431055 |
7 | 1025342316434612 |
oct | 111010652721253 |
9 | 18680518731308 |
10 | 5017707455147 |
11 | 1664aa8057712 |
12 | 6905700a848b |
13 | 2a522480718a |
14 | 134c033c0879 |
15 | 8a7c708ecd2 |
hex | 49046aba2ab |
5017707455147 has 2 divisors, whose sum is σ = 5017707455148. Its totient is φ = 5017707455146.
The previous prime is 5017707455113. The next prime is 5017707455161. The reversal of 5017707455147 is 7415547077105.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5017707455147 - 212 = 5017707451051 is a prime.
It is not a weakly prime, because it can be changed into another prime (5017707455177) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2508853727573 + 2508853727574.
It is an arithmetic number, because the mean of its divisors is an integer number (2508853727574).
Almost surely, 25017707455147 is an apocalyptic number.
5017707455147 is a deficient number, since it is larger than the sum of its proper divisors (1).
5017707455147 is an equidigital number, since it uses as much as digits as its factorization.
5017707455147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4802000, while the sum is 53.
The spelling of 5017707455147 in words is "five trillion, seventeen billion, seven hundred seven million, four hundred fifty-five thousand, one hundred forty-seven".
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