502013112019 has 2 divisors, whose sum is σ = 502013112020. Its totient is φ = 502013112018.

The previous prime is 502013111993. The next prime is 502013112023. The reversal of 502013112019 is 910211310205.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 502013112019 - 2⁵ = 502013111987 is a prime.

It is a super-2 number, since 2×502013112019² (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 502013111984 and 502013112002.

It is not a weakly prime, because it can be changed into another prime (502013112059) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 251006556009 + 251006556010.

It is an arithmetic number, because the mean of its divisors is an integer number (251006556010).

Almost surely, 2^502013112019 is an apocalyptic number.

502013112019 is a deficient number, since it is larger than the sum of its proper divisors (1).

502013112019 is an equidigital number, since it uses as much as digits as its factorization.

502013112019 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 540, while the sum is 25.

The spelling of 502013112019 in words is "five hundred two billion, thirteen million, one hundred twelve thousand, nineteen".