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5020302544721 is a prime number
BaseRepresentation
bin100100100001110000101…
…0110011000111101010001
3122202221021111221020222222
41021003201112120331101
51124223034422412341
614402143430310425
71025463530354462
oct111034126307521
918687244836888
105020302544721
1116661099a8942
12690b751b8415
132a554934b039
14134dabd04d69
158a8c9d0044b
hex490e1598f51

5020302544721 has 2 divisors, whose sum is σ = 5020302544722. Its totient is φ = 5020302544720.

The previous prime is 5020302544717. The next prime is 5020302544723. The reversal of 5020302544721 is 1274452030205.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4427573472400 + 592729072321 = 2104180^2 + 769889^2 .

It is a cyclic number.

It is not a de Polignac number, because 5020302544721 - 22 = 5020302544717 is a prime.

Together with 5020302544723, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (5020302544723) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2510151272360 + 2510151272361.

It is an arithmetic number, because the mean of its divisors is an integer number (2510151272361).

Almost surely, 25020302544721 is an apocalyptic number.

It is an amenable number.

5020302544721 is a deficient number, since it is larger than the sum of its proper divisors (1).

5020302544721 is an equidigital number, since it uses as much as digits as its factorization.

5020302544721 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 67200, while the sum is 35.

Adding to 5020302544721 its reverse (1274452030205), we get a palindrome (6294754574926).

The spelling of 5020302544721 in words is "five trillion, twenty billion, three hundred two million, five hundred forty-four thousand, seven hundred twenty-one".