Base | Representation |
---|---|
bin | 100100100001110001111… |
… | …0001001110010010000101 |
3 | 122202221101100022101002022 |
4 | 1021003203301032102011 |
5 | 1124223130320231232 |
6 | 14402151440252525 |
7 | 1025464532353541 |
oct | 111034361162205 |
9 | 18687340271068 |
10 | 5020343133317 |
11 | 166612a900736 |
12 | 690b86911145 |
13 | 2a555488c765 |
14 | 134db346ca21 |
15 | 8a8cd66b812 |
hex | 490e3c4e485 |
5020343133317 has 2 divisors, whose sum is σ = 5020343133318. Its totient is φ = 5020343133316.
The previous prime is 5020343133277. The next prime is 5020343133341. The reversal of 5020343133317 is 7133313430205.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4261412933761 + 758930199556 = 2064319^2 + 871166^2 .
It is a cyclic number.
It is not a de Polignac number, because 5020343133317 - 28 = 5020343133061 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5020343133347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2510171566658 + 2510171566659.
It is an arithmetic number, because the mean of its divisors is an integer number (2510171566659).
Almost surely, 25020343133317 is an apocalyptic number.
It is an amenable number.
5020343133317 is a deficient number, since it is larger than the sum of its proper divisors (1).
5020343133317 is an equidigital number, since it uses as much as digits as its factorization.
5020343133317 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 68040, while the sum is 35.
The spelling of 5020343133317 in words is "five trillion, twenty billion, three hundred forty-three million, one hundred thirty-three thousand, three hundred seventeen".
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