Base | Representation |
---|---|
bin | 111001000100111010101111… |
… | …1100010111110100101110001 |
3 | 2102211121211002210002111121202 |
4 | 1302021311133202332211301 |
5 | 1011301114441033323423 |
6 | 4535440021335500545 |
7 | 210515101460566244 |
oct | 16211653742764561 |
9 | 2384554083074552 |
10 | 502053215136113 |
11 | 135a73633497a93 |
12 | 48385339b27755 |
13 | 1871a551b05b84 |
14 | 8bd971064525b |
15 | 3d0985265d728 |
hex | 1c89d5f8be971 |
502053215136113 has 2 divisors, whose sum is σ = 502053215136114. Its totient is φ = 502053215136112.
The previous prime is 502053215136013. The next prime is 502053215136173. The reversal of 502053215136113 is 311631512350205.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 336221071214224 + 165832143921889 = 18336332^2 + 12877583^2 .
It is a cyclic number.
It is not a de Polignac number, because 502053215136113 - 222 = 502053210941809 is a prime.
It is not a weakly prime, because it can be changed into another prime (502053215136173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 251026607568056 + 251026607568057.
It is an arithmetic number, because the mean of its divisors is an integer number (251026607568057).
Almost surely, 2502053215136113 is an apocalyptic number.
It is an amenable number.
502053215136113 is a deficient number, since it is larger than the sum of its proper divisors (1).
502053215136113 is an equidigital number, since it uses as much as digits as its factorization.
502053215136113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81000, while the sum is 38.
Adding to 502053215136113 its reverse (311631512350205), we get a palindrome (813684727486318).
The spelling of 502053215136113 in words is "five hundred two trillion, fifty-three billion, two hundred fifteen million, one hundred thirty-six thousand, one hundred thirteen".
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