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502053215136113 is a prime number
BaseRepresentation
bin111001000100111010101111…
…1100010111110100101110001
32102211121211002210002111121202
41302021311133202332211301
51011301114441033323423
64535440021335500545
7210515101460566244
oct16211653742764561
92384554083074552
10502053215136113
11135a73633497a93
1248385339b27755
131871a551b05b84
148bd971064525b
153d0985265d728
hex1c89d5f8be971

502053215136113 has 2 divisors, whose sum is σ = 502053215136114. Its totient is φ = 502053215136112.

The previous prime is 502053215136013. The next prime is 502053215136173. The reversal of 502053215136113 is 311631512350205.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 336221071214224 + 165832143921889 = 18336332^2 + 12877583^2 .

It is a cyclic number.

It is not a de Polignac number, because 502053215136113 - 222 = 502053210941809 is a prime.

It is not a weakly prime, because it can be changed into another prime (502053215136173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 251026607568056 + 251026607568057.

It is an arithmetic number, because the mean of its divisors is an integer number (251026607568057).

Almost surely, 2502053215136113 is an apocalyptic number.

It is an amenable number.

502053215136113 is a deficient number, since it is larger than the sum of its proper divisors (1).

502053215136113 is an equidigital number, since it uses as much as digits as its factorization.

502053215136113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 81000, while the sum is 38.

Adding to 502053215136113 its reverse (311631512350205), we get a palindrome (813684727486318).

The spelling of 502053215136113 in words is "five hundred two trillion, fifty-three billion, two hundred fifteen million, one hundred thirty-six thousand, one hundred thirteen".