Base | Representation |
---|---|
bin | 100100100010001001011… |
… | …1011000010000111110011 |
3 | 122210000102110220110100021 |
4 | 1021010102323002013303 |
5 | 1124231240330442344 |
6 | 14402402140304311 |
7 | 1025523246534034 |
oct | 111042273020763 |
9 | 18700373813307 |
10 | 5021134234099 |
11 | 16664a6413435 |
12 | 691167842097 |
13 | 2a564c747b29 |
14 | 13504a55ca8b |
15 | 8a927d36b84 |
hex | 49112ec21f3 |
5021134234099 has 2 divisors, whose sum is σ = 5021134234100. Its totient is φ = 5021134234098.
The previous prime is 5021134234097. The next prime is 5021134234121. The reversal of 5021134234099 is 9904324311205.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5021134234099 - 21 = 5021134234097 is a prime.
Together with 5021134234097, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (5021134234097) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2510567117049 + 2510567117050.
It is an arithmetic number, because the mean of its divisors is an integer number (2510567117050).
Almost surely, 25021134234099 is an apocalyptic number.
5021134234099 is a deficient number, since it is larger than the sum of its proper divisors (1).
5021134234099 is an equidigital number, since it uses as much as digits as its factorization.
5021134234099 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 233280, while the sum is 43.
The spelling of 5021134234099 in words is "five trillion, twenty-one billion, one hundred thirty-four million, two hundred thirty-four thousand, ninety-nine".
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