Base | Representation |
---|---|
bin | 10110110101011000000111… |
… | …01101111100001000001111 |
3 | 20120210021022012111111102112 |
4 | 23122230003231330020033 |
5 | 23040140222402010301 |
6 | 254443152054214235 |
7 | 13401510115403222 |
oct | 1332540355741017 |
9 | 216707265444375 |
10 | 50212525031951 |
11 | 14aaa015385167 |
12 | 576b63505437b |
13 | 22030368b4659 |
14 | c58428d375b9 |
15 | 5c12229b49bb |
hex | 2dab03b7c20f |
50212525031951 has 2 divisors, whose sum is σ = 50212525031952. Its totient is φ = 50212525031950.
The previous prime is 50212525031947. The next prime is 50212525031993. The reversal of 50212525031951 is 15913052521205.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 50212525031951 - 22 = 50212525031947 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 50212525031899 and 50212525031908.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (50212525030951) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25106262515975 + 25106262515976.
It is an arithmetic number, because the mean of its divisors is an integer number (25106262515976).
Almost surely, 250212525031951 is an apocalyptic number.
50212525031951 is a deficient number, since it is larger than the sum of its proper divisors (1).
50212525031951 is an equidigital number, since it uses as much as digits as its factorization.
50212525031951 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 135000, while the sum is 41.
The spelling of 50212525031951 in words is "fifty trillion, two hundred twelve billion, five hundred twenty-five million, thirty-one thousand, nine hundred fifty-one".
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