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50212525031951 is a prime number
BaseRepresentation
bin10110110101011000000111…
…01101111100001000001111
320120210021022012111111102112
423122230003231330020033
523040140222402010301
6254443152054214235
713401510115403222
oct1332540355741017
9216707265444375
1050212525031951
1114aaa015385167
12576b63505437b
1322030368b4659
14c58428d375b9
155c12229b49bb
hex2dab03b7c20f

50212525031951 has 2 divisors, whose sum is σ = 50212525031952. Its totient is φ = 50212525031950.

The previous prime is 50212525031947. The next prime is 50212525031993. The reversal of 50212525031951 is 15913052521205.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 50212525031951 - 22 = 50212525031947 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 50212525031899 and 50212525031908.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (50212525030951) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25106262515975 + 25106262515976.

It is an arithmetic number, because the mean of its divisors is an integer number (25106262515976).

Almost surely, 250212525031951 is an apocalyptic number.

50212525031951 is a deficient number, since it is larger than the sum of its proper divisors (1).

50212525031951 is an equidigital number, since it uses as much as digits as its factorization.

50212525031951 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 135000, while the sum is 41.

The spelling of 50212525031951 in words is "fifty trillion, two hundred twelve billion, five hundred twenty-five million, thirty-one thousand, nine hundred fifty-one".