Base | Representation |
---|---|
bin | 10110110101011111001101… |
… | …01101100100000001000001 |
3 | 20120210122010121112200001121 |
4 | 23122233212231210001001 |
5 | 23040221022320024332 |
6 | 254445022020032241 |
7 | 13402003360563052 |
oct | 1332574655440101 |
9 | 216718117480047 |
10 | 50216333361217 |
11 | 1500069a055321 |
12 | 5770318532681 |
13 | 22034c28a701a |
14 | c586aaa36729 |
15 | 5c1396ec8797 |
hex | 2dabe6b64041 |
50216333361217 has 2 divisors, whose sum is σ = 50216333361218. Its totient is φ = 50216333361216.
The previous prime is 50216333361167. The next prime is 50216333361241. The reversal of 50216333361217 is 71216333361205.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 32330868928576 + 17885464432641 = 5686024^2 + 4229121^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-50216333361217 is a prime.
It is not a weakly prime, because it can be changed into another prime (50216333061217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25108166680608 + 25108166680609.
It is an arithmetic number, because the mean of its divisors is an integer number (25108166680609).
Almost surely, 250216333361217 is an apocalyptic number.
It is an amenable number.
50216333361217 is a deficient number, since it is larger than the sum of its proper divisors (1).
50216333361217 is an equidigital number, since it uses as much as digits as its factorization.
50216333361217 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 408240, while the sum is 43.
The spelling of 50216333361217 in words is "fifty trillion, two hundred sixteen billion, three hundred thirty-three million, three hundred sixty-one thousand, two hundred seventeen".
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