Base | Representation |
---|---|
bin | 1001010110101011… |
… | …00000001011110001 |
3 | 110221222211021101221 |
4 | 10223111200023301 |
5 | 40241114240213 |
6 | 2150155225041 |
7 | 235310334436 |
oct | 45325401361 |
9 | 13858737357 |
10 | 5022024433 |
11 | 2147890318 |
12 | b81a48181 |
13 | 6205a05ba |
14 | 358d95b8d |
15 | 1e5d5738d |
hex | 12b5602f1 |
5022024433 has 2 divisors, whose sum is σ = 5022024434. Its totient is φ = 5022024432.
The previous prime is 5022024421. The next prime is 5022024437. The reversal of 5022024433 is 3344202205.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4993966224 + 28058209 = 70668^2 + 5297^2 .
It is a cyclic number.
It is not a de Polignac number, because 5022024433 - 217 = 5021893361 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5022024398 and 5022024407.
It is not a weakly prime, because it can be changed into another prime (5022024437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2511012216 + 2511012217.
It is an arithmetic number, because the mean of its divisors is an integer number (2511012217).
Almost surely, 25022024433 is an apocalyptic number.
It is an amenable number.
5022024433 is a deficient number, since it is larger than the sum of its proper divisors (1).
5022024433 is an equidigital number, since it uses as much as digits as its factorization.
5022024433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5760, while the sum is 25.
The square root of 5022024433 is about 70866.2432544579. The cubic root of 5022024433 is about 1712.4830191933.
Adding to 5022024433 its reverse (3344202205), we get a palindrome (8366226638).
The spelling of 5022024433 in words is "five billion, twenty-two million, twenty-four thousand, four hundred thirty-three".
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