Base | Representation |
---|---|
bin | 101110110001011011… |
… | …000111101110111101 |
3 | 11210122000021020112202 |
4 | 232301123013232331 |
5 | 1310323124121203 |
6 | 35023225041245 |
7 | 3425350102655 |
oct | 566133075675 |
9 | 153560236482 |
10 | 50221317053 |
11 | 1a331695906 |
12 | 9897026225 |
13 | 497487ba6b |
14 | 2605ca1365 |
15 | 148e010388 |
hex | bb16c7bbd |
50221317053 has 2 divisors, whose sum is σ = 50221317054. Its totient is φ = 50221317052.
The previous prime is 50221317001. The next prime is 50221317071. The reversal of 50221317053 is 35071312205.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 31862964004 + 18358353049 = 178502^2 + 135493^2 .
It is a cyclic number.
It is not a de Polignac number, because 50221317053 - 28 = 50221316797 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (50221313053) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25110658526 + 25110658527.
It is an arithmetic number, because the mean of its divisors is an integer number (25110658527).
Almost surely, 250221317053 is an apocalyptic number.
It is an amenable number.
50221317053 is a deficient number, since it is larger than the sum of its proper divisors (1).
50221317053 is an equidigital number, since it uses as much as digits as its factorization.
50221317053 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6300, while the sum is 29.
Adding to 50221317053 its reverse (35071312205), we get a palindrome (85292629258).
The spelling of 50221317053 in words is "fifty billion, two hundred twenty-one million, three hundred seventeen thousand, fifty-three".
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