Base | Representation |
---|---|
bin | 100100100010110001000… |
… | …1001000111011110110011 |
3 | 122210010212002211022212002 |
4 | 1021011202021013132303 |
5 | 1124242001102414011 |
6 | 14403142055324215 |
7 | 1025601215611646 |
oct | 111054211073663 |
9 | 18703762738762 |
10 | 5022463326131 |
11 | 16670186809a9 |
12 | 69147898066b |
13 | 2a5801bca714 |
14 | 135134c93a5d |
15 | 8a9a4871c3b |
hex | 491622477b3 |
5022463326131 has 2 divisors, whose sum is σ = 5022463326132. Its totient is φ = 5022463326130.
The previous prime is 5022463326053. The next prime is 5022463326163. The reversal of 5022463326131 is 1316233642205.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5022463326131 - 210 = 5022463325107 is a prime.
It is a super-2 number, since 2×50224633261312 (a number of 26 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (5022463326191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2511231663065 + 2511231663066.
It is an arithmetic number, because the mean of its divisors is an integer number (2511231663066).
Almost surely, 25022463326131 is an apocalyptic number.
5022463326131 is a deficient number, since it is larger than the sum of its proper divisors (1).
5022463326131 is an equidigital number, since it uses as much as digits as its factorization.
5022463326131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 155520, while the sum is 38.
Adding to 5022463326131 its reverse (1316233642205), we get a palindrome (6338696968336).
The spelling of 5022463326131 in words is "five trillion, twenty-two billion, four hundred sixty-three million, three hundred twenty-six thousand, one hundred thirty-one".
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