Base | Representation |
---|---|
bin | 10110110101111010100111… |
… | …00011000111011111000111 |
3 | 20120212001002211122210211222 |
4 | 23122331103203013133013 |
5 | 23040441134311210401 |
6 | 254455453445150555 |
7 | 13403034050156321 |
oct | 1332752343073707 |
9 | 216761084583758 |
10 | 50231044241351 |
11 | 15006958a542a6 |
12 | 57731430bb45b |
13 | 22049c856461c |
14 | c592a46ba611 |
15 | 5c195872cc1b |
hex | 2daf538c77c7 |
50231044241351 has 2 divisors, whose sum is σ = 50231044241352. Its totient is φ = 50231044241350.
The previous prime is 50231044241309. The next prime is 50231044241363. The reversal of 50231044241351 is 15314244013205.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-50231044241351 is a prime.
It is a super-2 number, since 2×502310442413512 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (50231044241251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25115522120675 + 25115522120676.
It is an arithmetic number, because the mean of its divisors is an integer number (25115522120676).
Almost surely, 250231044241351 is an apocalyptic number.
50231044241351 is a deficient number, since it is larger than the sum of its proper divisors (1).
50231044241351 is an equidigital number, since it uses as much as digits as its factorization.
50231044241351 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 57600, while the sum is 35.
Adding to 50231044241351 its reverse (15314244013205), we get a palindrome (65545288254556).
The spelling of 50231044241351 in words is "fifty trillion, two hundred thirty-one billion, forty-four million, two hundred forty-one thousand, three hundred fifty-one".
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