Base | Representation |
---|---|
bin | 100100100100000110100… |
… | …0101101010010011011001 |
3 | 122210102020222110201110212 |
4 | 1021020031011222103121 |
5 | 1124313334304332441 |
6 | 14404334430420505 |
7 | 1026032252315063 |
oct | 111101505522331 |
9 | 18712228421425 |
10 | 5025331324121 |
11 | 166825a582279 |
12 | 691b39361735 |
13 | 2a5b6b145154 |
14 | 135327b38733 |
15 | 8aac153deeb |
hex | 4920d16a4d9 |
5025331324121 has 2 divisors, whose sum is σ = 5025331324122. Its totient is φ = 5025331324120.
The previous prime is 5025331324093. The next prime is 5025331324171. The reversal of 5025331324121 is 1214231335205.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4800218083600 + 225113240521 = 2190940^2 + 474461^2 .
It is a cyclic number.
It is not a de Polignac number, because 5025331324121 - 210 = 5025331323097 is a prime.
It is not a weakly prime, because it can be changed into another prime (5025331324171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2512665662060 + 2512665662061.
It is an arithmetic number, because the mean of its divisors is an integer number (2512665662061).
Almost surely, 25025331324121 is an apocalyptic number.
It is an amenable number.
5025331324121 is a deficient number, since it is larger than the sum of its proper divisors (1).
5025331324121 is an equidigital number, since it uses as much as digits as its factorization.
5025331324121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21600, while the sum is 32.
Adding to 5025331324121 its reverse (1214231335205), we get a palindrome (6239562659326).
The spelling of 5025331324121 in words is "five trillion, twenty-five billion, three hundred thirty-one million, three hundred twenty-four thousand, one hundred twenty-one".
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