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5025331324193 is a prime number
BaseRepresentation
bin100100100100000110100…
…0101101010010100100001
3122210102020222110201120112
41021020031011222110201
51124313334304333233
614404334430421105
71026032252315225
oct111101505522441
918712228421515
105025331324193
11166825a582334
12691b39361795
132a5b6b1451ab
14135327b38785
158aac153e048
hex4920d16a521

5025331324193 has 2 divisors, whose sum is σ = 5025331324194. Its totient is φ = 5025331324192.

The previous prime is 5025331324177. The next prime is 5025331324207. The reversal of 5025331324193 is 3914231335205.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4739381248144 + 285950076049 = 2177012^2 + 534743^2 .

It is a cyclic number.

It is not a de Polignac number, because 5025331324193 - 24 = 5025331324177 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 5025331324193.

It is not a weakly prime, because it can be changed into another prime (5025331324093) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2512665662096 + 2512665662097.

It is an arithmetic number, because the mean of its divisors is an integer number (2512665662097).

Almost surely, 25025331324193 is an apocalyptic number.

It is an amenable number.

5025331324193 is a deficient number, since it is larger than the sum of its proper divisors (1).

5025331324193 is an equidigital number, since it uses as much as digits as its factorization.

5025331324193 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 291600, while the sum is 41.

Adding to 5025331324193 its reverse (3914231335205), we get a palindrome (8939562659398).

The spelling of 5025331324193 in words is "five trillion, twenty-five billion, three hundred thirty-one million, three hundred twenty-four thousand, one hundred ninety-three".