Base | Representation |
---|---|
bin | 100100100100001000111… |
… | …0101111000000000001101 |
3 | 122210102110112112100000111 |
4 | 1021020101311320000031 |
5 | 1124314020213301023 |
6 | 14404350400000021 |
7 | 1026034241211163 |
oct | 111102165700015 |
9 | 18712415470014 |
10 | 5025411072013 |
11 | 16682a05a1022 |
12 | 691b60000011 |
13 | 2a5b81817857 |
14 | 135334577233 |
15 | 8aac854300d |
hex | 49211d7800d |
5025411072013 has 2 divisors, whose sum is σ = 5025411072014. Its totient is φ = 5025411072012.
The previous prime is 5025411071951. The next prime is 5025411072023. The reversal of 5025411072013 is 3102701145205.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4264402591849 + 761008480164 = 2065043^2 + 872358^2 .
It is a cyclic number.
It is not a de Polignac number, because 5025411072013 - 225 = 5025377517581 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5025411072023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2512705536006 + 2512705536007.
It is an arithmetic number, because the mean of its divisors is an integer number (2512705536007).
Almost surely, 25025411072013 is an apocalyptic number.
It is an amenable number.
5025411072013 is a deficient number, since it is larger than the sum of its proper divisors (1).
5025411072013 is an equidigital number, since it uses as much as digits as its factorization.
5025411072013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8400, while the sum is 31.
The spelling of 5025411072013 in words is "five trillion, twenty-five billion, four hundred eleven million, seventy-two thousand, thirteen".
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