Base | Representation |
---|---|
bin | 101110110100101000… |
… | …000110001000000101 |
3 | 11210202202101011021111 |
4 | 232310220012020011 |
5 | 1310430403044424 |
6 | 35032424445021 |
7 | 3426601605523 |
oct | 566450061005 |
9 | 153682334244 |
10 | 50275049989 |
11 | 1a359a5619a |
12 | 98b1019771 |
13 | 4982a432b8 |
14 | 260d08b313 |
15 | 1493ac6194 |
hex | bb4a06205 |
50275049989 has 2 divisors, whose sum is σ = 50275049990. Its totient is φ = 50275049988.
The previous prime is 50275049963. The next prime is 50275050037. The reversal of 50275049989 is 98994057205.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 40268448900 + 10006601089 = 200670^2 + 100033^2 .
It is a cyclic number.
It is not a de Polignac number, because 50275049989 - 223 = 50266661381 is a prime.
It is a super-3 number, since 3×502750499893 (a number of 33 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (50275049189) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25137524994 + 25137524995.
It is an arithmetic number, because the mean of its divisors is an integer number (25137524995).
Almost surely, 250275049989 is an apocalyptic number.
It is an amenable number.
50275049989 is a deficient number, since it is larger than the sum of its proper divisors (1).
50275049989 is an equidigital number, since it uses as much as digits as its factorization.
50275049989 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8164800, while the sum is 58.
The spelling of 50275049989 in words is "fifty billion, two hundred seventy-five million, forty-nine thousand, nine hundred eighty-nine".
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