Base | Representation |
---|---|
bin | 10110111000001111100100… |
… | …00000111010111000101111 |
3 | 20121010200111221121100020212 |
4 | 23130013302000322320233 |
5 | 23043243423114444034 |
6 | 255000320541333035 |
7 | 13411564533153035 |
oct | 1334076200727057 |
9 | 217120457540225 |
10 | 50311012265519 |
11 | 15037864900475 |
12 | 578674026717b |
13 | 220c400b82015 |
14 | c5d0cd0d0555 |
15 | 5c3a88ed22ce |
hex | 2dc1f203ae2f |
50311012265519 has 2 divisors, whose sum is σ = 50311012265520. Its totient is φ = 50311012265518.
The previous prime is 50311012265483. The next prime is 50311012265533. The reversal of 50311012265519 is 91556221011305.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-50311012265519 is a prime.
It is a super-2 number, since 2×503110122655192 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (50311012265119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25155506132759 + 25155506132760.
It is an arithmetic number, because the mean of its divisors is an integer number (25155506132760).
Almost surely, 250311012265519 is an apocalyptic number.
50311012265519 is a deficient number, since it is larger than the sum of its proper divisors (1).
50311012265519 is an equidigital number, since it uses as much as digits as its factorization.
50311012265519 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81000, while the sum is 41.
The spelling of 50311012265519 in words is "fifty trillion, three hundred eleven billion, twelve million, two hundred sixty-five thousand, five hundred nineteen".
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