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50314739400593 is a prime number
BaseRepresentation
bin10110111000010110100000…
…01010110011111110010001
320121011001010200212102101122
423130023100022303332101
523043324041241304333
6255002134443012025
713412056101244043
oct1334132012637621
9217131120772348
1050314739400593
11150393a7764198
12578740050a015
13220c8760b68a5
14c5d3640d5a93
155c3c06308798
hex2dc2d02b3f91

50314739400593 has 2 divisors, whose sum is σ = 50314739400594. Its totient is φ = 50314739400592.

The previous prime is 50314739400529. The next prime is 50314739400613. The reversal of 50314739400593 is 39500493741305.

50314739400593 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 49955252817409 + 359486583184 = 7067903^2 + 599572^2 .

It is a cyclic number.

It is not a de Polignac number, because 50314739400593 - 26 = 50314739400529 is a prime.

It is not a weakly prime, because it can be changed into another prime (50314739400193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25157369700296 + 25157369700297.

It is an arithmetic number, because the mean of its divisors is an integer number (25157369700297).

Almost surely, 250314739400593 is an apocalyptic number.

It is an amenable number.

50314739400593 is a deficient number, since it is larger than the sum of its proper divisors (1).

50314739400593 is an equidigital number, since it uses as much as digits as its factorization.

50314739400593 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6123600, while the sum is 53.

The spelling of 50314739400593 in words is "fifty trillion, three hundred fourteen billion, seven hundred thirty-nine million, four hundred thousand, five hundred ninety-three".