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50320440417133 is a prime number
BaseRepresentation
bin10110111000100001000111…
…11110011101101101101101
320121011120212000100001212101
423130100203332131231231
523043422230221322013
6255004520255335101
713412350265135365
oct1334204376355555
9217146760301771
1050320440417133
1115040862845307
125788531821491
13221027424c463
14c5d7453179a5
155c3e3ba838dd
hex2dc423f9db6d

50320440417133 has 2 divisors, whose sum is σ = 50320440417134. Its totient is φ = 50320440417132.

The previous prime is 50320440417083. The next prime is 50320440417251. The reversal of 50320440417133 is 33171404402305.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 50238794212489 + 81646204644 = 7087933^2 + 285738^2 .

It is a cyclic number.

It is not a de Polignac number, because 50320440417133 - 229 = 50319903546221 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 50320440417092 and 50320440417101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (50320447417133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25160220208566 + 25160220208567.

It is an arithmetic number, because the mean of its divisors is an integer number (25160220208567).

Almost surely, 250320440417133 is an apocalyptic number.

It is an amenable number.

50320440417133 is a deficient number, since it is larger than the sum of its proper divisors (1).

50320440417133 is an equidigital number, since it uses as much as digits as its factorization.

50320440417133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 120960, while the sum is 37.

Adding to 50320440417133 its reverse (33171404402305), we get a palindrome (83491844819438).

The spelling of 50320440417133 in words is "fifty trillion, three hundred twenty billion, four hundred forty million, four hundred seventeen thousand, one hundred thirty-three".