Base | Representation |
---|---|
bin | 10110111000100001001000… |
… | …00001010100011110000011 |
3 | 20121011120212001202002201001 |
4 | 23130100210001110132003 |
5 | 23043422230414300244 |
6 | 255004520323352431 |
7 | 13412350304403655 |
oct | 1334204401243603 |
9 | 217146761662631 |
10 | 50320441165699 |
11 | 15040863206761 |
12 | 5788531b22717 |
13 | 22102744520b3 |
14 | c5d7454706d5 |
15 | 5c3e3bb805d4 |
hex | 2dc424054783 |
50320441165699 has 2 divisors, whose sum is σ = 50320441165700. Its totient is φ = 50320441165698.
The previous prime is 50320441165651. The next prime is 50320441165723. The reversal of 50320441165699 is 99656114402305.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 50320441165699 - 225 = 50320407611267 is a prime.
It is a super-3 number, since 3×503204411656993 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (50320441165639) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25160220582849 + 25160220582850.
It is an arithmetic number, because the mean of its divisors is an integer number (25160220582850).
Almost surely, 250320441165699 is an apocalyptic number.
50320441165699 is a deficient number, since it is larger than the sum of its proper divisors (1).
50320441165699 is an equidigital number, since it uses as much as digits as its factorization.
50320441165699 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6998400, while the sum is 55.
The spelling of 50320441165699 in words is "fifty trillion, three hundred twenty billion, four hundred forty-one million, one hundred sixty-five thousand, six hundred ninety-nine".
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