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50325200133041 is a prime number
BaseRepresentation
bin10110111000101001111111…
…01011010101101110110001
320121012001010201120200121202
423130110333223111232301
523044012002213224131
6255011024444500545
713412606242065221
oct1334247753255661
9217161121520552
1050325200133041
1115042885555319
12578943b84a755
13221085238aac2
14c5da7750c081
155c4119874bcb
hex2dc53fad5bb1

50325200133041 has 2 divisors, whose sum is σ = 50325200133042. Its totient is φ = 50325200133040.

The previous prime is 50325200132971. The next prime is 50325200133073. The reversal of 50325200133041 is 14033100252305.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 37829929564816 + 12495270568225 = 6150604^2 + 3534865^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-50325200133041 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 50325200132995 and 50325200133013.

It is not a weakly prime, because it can be changed into another prime (50325200133541) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25162600066520 + 25162600066521.

It is an arithmetic number, because the mean of its divisors is an integer number (25162600066521).

Almost surely, 250325200133041 is an apocalyptic number.

It is an amenable number.

50325200133041 is a deficient number, since it is larger than the sum of its proper divisors (1).

50325200133041 is an equidigital number, since it uses as much as digits as its factorization.

50325200133041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10800, while the sum is 29.

Adding to 50325200133041 its reverse (14033100252305), we get a palindrome (64358300385346).

The spelling of 50325200133041 in words is "fifty trillion, three hundred twenty-five billion, two hundred million, one hundred thirty-three thousand, forty-one".