Base | Representation |
---|---|
bin | 100100100111110010010… |
… | …0100101011001111000011 |
3 | 122211011200020220110120212 |
4 | 1021033210210223033003 |
5 | 1124431034312220024 |
6 | 14412123401424335 |
7 | 1026432263021564 |
oct | 111174444531703 |
9 | 18734606813525 |
10 | 5033241523139 |
11 | 1670649694935 |
12 | 69358649b0ab |
13 | 2a682bba5a9b |
14 | 13587850816b |
15 | 8add5beba0e |
hex | 493e492b3c3 |
5033241523139 has 2 divisors, whose sum is σ = 5033241523140. Its totient is φ = 5033241523138.
The previous prime is 5033241523111. The next prime is 5033241523151. The reversal of 5033241523139 is 9313251423305.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5033241523139 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5033241523096 and 5033241523105.
It is not a weakly prime, because it can be changed into another prime (5033241523439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2516620761569 + 2516620761570.
It is an arithmetic number, because the mean of its divisors is an integer number (2516620761570).
Almost surely, 25033241523139 is an apocalyptic number.
5033241523139 is a deficient number, since it is larger than the sum of its proper divisors (1).
5033241523139 is an equidigital number, since it uses as much as digits as its factorization.
5033241523139 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 291600, while the sum is 41.
The spelling of 5033241523139 in words is "five trillion, thirty-three billion, two hundred forty-one million, five hundred twenty-three thousand, one hundred thirty-nine".
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