Base | Representation |
---|---|
bin | 10110111000110111101011… |
… | …00000011000111101110101 |
3 | 20121012202002122112022021101 |
4 | 23130123311200120331311 |
5 | 23044122023143331232 |
6 | 255014241405250101 |
7 | 13413256255166542 |
oct | 1334336540307565 |
9 | 217182078468241 |
10 | 50332545683317 |
11 | 15045a04964a27 |
12 | 578a94b863931 |
13 | 221145314c761 |
14 | c60172cd7bc9 |
15 | 5c43e96991e7 |
hex | 2dc6f5818f75 |
50332545683317 has 2 divisors, whose sum is σ = 50332545683318. Its totient is φ = 50332545683316.
The previous prime is 50332545683279. The next prime is 50332545683339. The reversal of 50332545683317 is 71338654523305.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 48275690621041 + 2056855062276 = 6948071^2 + 1434174^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-50332545683317 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (50332545183317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25166272841658 + 25166272841659.
It is an arithmetic number, because the mean of its divisors is an integer number (25166272841659).
Almost surely, 250332545683317 is an apocalyptic number.
It is an amenable number.
50332545683317 is a deficient number, since it is larger than the sum of its proper divisors (1).
50332545683317 is an equidigital number, since it uses as much as digits as its factorization.
50332545683317 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27216000, while the sum is 55.
The spelling of 50332545683317 in words is "fifty trillion, three hundred thirty-two billion, five hundred forty-five million, six hundred eighty-three thousand, three hundred seventeen".
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