Base | Representation |
---|---|
bin | 100100100111110100011… |
… | …0011101000000101111011 |
3 | 122211011212012120001220011 |
4 | 1021033220303220011323 |
5 | 1124431211003120131 |
6 | 14412134420042351 |
7 | 1026434114530003 |
oct | 111175063500573 |
9 | 18734765501804 |
10 | 5033312551291 |
11 | 1670685798392 |
12 | 6935a62333b7 |
13 | 2a684081458b |
14 | 135883b17003 |
15 | 8addc07c0b1 |
hex | 493e8ce817b |
5033312551291 has 2 divisors, whose sum is σ = 5033312551292. Its totient is φ = 5033312551290.
The previous prime is 5033312551273. The next prime is 5033312551307. The reversal of 5033312551291 is 1921552133305.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5033312551291 - 213 = 5033312543099 is a prime.
It is not a weakly prime, because it can be changed into another prime (5033312051291) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2516656275645 + 2516656275646.
It is an arithmetic number, because the mean of its divisors is an integer number (2516656275646).
Almost surely, 25033312551291 is an apocalyptic number.
5033312551291 is a deficient number, since it is larger than the sum of its proper divisors (1).
5033312551291 is an equidigital number, since it uses as much as digits as its factorization.
5033312551291 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 121500, while the sum is 40.
Adding to 5033312551291 its reverse (1921552133305), we get a palindrome (6954864684596).
The spelling of 5033312551291 in words is "five trillion, thirty-three billion, three hundred twelve million, five hundred fifty-one thousand, two hundred ninety-one".
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