Base | Representation |
---|---|
bin | 100100100111110100011… |
… | …0011101000000110001011 |
3 | 122211011212012120001220202 |
4 | 1021033220303220012023 |
5 | 1124431211003120212 |
6 | 14412134420042415 |
7 | 1026434114530025 |
oct | 111175063500613 |
9 | 18734765501822 |
10 | 5033312551307 |
11 | 16706857983a7 |
12 | 6935a623340b |
13 | 2a68408145a1 |
14 | 135883b17015 |
15 | 8addc07c0c2 |
hex | 493e8ce818b |
5033312551307 has 2 divisors, whose sum is σ = 5033312551308. Its totient is φ = 5033312551306.
The previous prime is 5033312551291. The next prime is 5033312551321. The reversal of 5033312551307 is 7031552133305.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5033312551307 - 24 = 5033312551291 is a prime.
It is not a weakly prime, because it can be changed into another prime (5033312551367) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2516656275653 + 2516656275654.
It is an arithmetic number, because the mean of its divisors is an integer number (2516656275654).
Almost surely, 25033312551307 is an apocalyptic number.
5033312551307 is a deficient number, since it is larger than the sum of its proper divisors (1).
5033312551307 is an equidigital number, since it uses as much as digits as its factorization.
5033312551307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 141750, while the sum is 38.
The spelling of 5033312551307 in words is "five trillion, thirty-three billion, three hundred twelve million, five hundred fifty-one thousand, three hundred seven".
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