Base | Representation |
---|---|
bin | 1110101001100011010… |
… | …10100101010010101101 |
3 | 1210010012221022212000102 |
4 | 13110301222211102231 |
5 | 31221322132420023 |
6 | 1023122213440445 |
7 | 51236225656121 |
oct | 7246152452255 |
9 | 1703187285012 |
10 | 503344420013 |
11 | 184515891786 |
12 | 81675040125 |
13 | 38607cb3726 |
14 | 1a50d483581 |
15 | d15e55c628 |
hex | 7531aa54ad |
503344420013 has 2 divisors, whose sum is σ = 503344420014. Its totient is φ = 503344420012.
The previous prime is 503344419971. The next prime is 503344420021. The reversal of 503344420013 is 310024443305.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 447939734089 + 55404685924 = 669283^2 + 235382^2 .
It is a cyclic number.
It is not a de Polignac number, because 503344420013 - 210 = 503344418989 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (503344440013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 251672210006 + 251672210007.
It is an arithmetic number, because the mean of its divisors is an integer number (251672210007).
Almost surely, 2503344420013 is an apocalyptic number.
It is an amenable number.
503344420013 is a deficient number, since it is larger than the sum of its proper divisors (1).
503344420013 is an equidigital number, since it uses as much as digits as its factorization.
503344420013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17280, while the sum is 29.
Adding to 503344420013 its reverse (310024443305), we get a palindrome (813368863318).
The spelling of 503344420013 in words is "five hundred three billion, three hundred forty-four million, four hundred twenty thousand, thirteen".
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