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5034311143097 is a prime number
BaseRepresentation
bin100100101000010010001…
…0100111100111010111001
3122211021102210120210022212
41021100210110330322321
51124440232123034342
614412421451224505
71026500631444245
oct111204424747271
918737383523285
105034311143097
11167104843a175
12693824748135
132a696c67a7c2
1413593a5b9425
158ae49a81182
hex4942453ceb9

5034311143097 has 2 divisors, whose sum is σ = 5034311143098. Its totient is φ = 5034311143096.

The previous prime is 5034311143091. The next prime is 5034311143151. The reversal of 5034311143097 is 7903411134305.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3424587118096 + 1609724025001 = 1850564^2 + 1268749^2 .

It is a cyclic number.

It is not a de Polignac number, because 5034311143097 - 226 = 5034244034233 is a prime.

It is not a weakly prime, because it can be changed into another prime (5034311143091) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2517155571548 + 2517155571549.

It is an arithmetic number, because the mean of its divisors is an integer number (2517155571549).

Almost surely, 25034311143097 is an apocalyptic number.

It is an amenable number.

5034311143097 is a deficient number, since it is larger than the sum of its proper divisors (1).

5034311143097 is an equidigital number, since it uses as much as digits as its factorization.

5034311143097 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 136080, while the sum is 41.

The spelling of 5034311143097 in words is "five trillion, thirty-four billion, three hundred eleven million, one hundred forty-three thousand, ninety-seven".