Base | Representation |
---|---|
bin | 100100101000010010001… |
… | …0100111100111011101111 |
3 | 122211021102210120210101212 |
4 | 1021100210110330323233 |
5 | 1124440232123040101 |
6 | 14412421451225035 |
7 | 1026500631444353 |
oct | 111204424747357 |
9 | 18737383523355 |
10 | 5034311143151 |
11 | 167104843a214 |
12 | 69382474817b |
13 | 2a696c67a834 |
14 | 13593a5b9463 |
15 | 8ae49a811bb |
hex | 4942453ceef |
5034311143151 has 2 divisors, whose sum is σ = 5034311143152. Its totient is φ = 5034311143150.
The previous prime is 5034311143097. The next prime is 5034311143157. The reversal of 5034311143151 is 1513411134305.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5034311143151 - 218 = 5034310881007 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5034311143157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2517155571575 + 2517155571576.
It is an arithmetic number, because the mean of its divisors is an integer number (2517155571576).
Almost surely, 25034311143151 is an apocalyptic number.
5034311143151 is a deficient number, since it is larger than the sum of its proper divisors (1).
5034311143151 is an equidigital number, since it uses as much as digits as its factorization.
5034311143151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10800, while the sum is 32.
Adding to 5034311143151 its reverse (1513411134305), we get a palindrome (6547722277456).
The spelling of 5034311143151 in words is "five trillion, thirty-four billion, three hundred eleven million, one hundred forty-three thousand, one hundred fifty-one".
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