5034311143153 has 4 divisors (see below), whose sum is σ = 5129298145908. Its totient is φ = 4939324140400.

The previous prime is 5034311143151. The next prime is 5034311143157. The reversal of 5034311143153 is 3513411134305.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3793099017744 + 1241212125409 = 1947588^2 + 1114097^2 .

It is a cyclic number.

It is not a de Polignac number, because 5034311143153 - 2¹ = 5034311143151 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5034311143151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 47493501298 + ... + 47493501403.

It is an arithmetic number, because the mean of its divisors is an integer number (1282324536477).

Almost surely, 2^{5034311143153} is an apocalyptic number.

5034311143153 is a gapful number since it is divisible by the number (53) formed by its first and last digit.

It is an amenable number.

5034311143153 is a deficient number, since it is larger than the sum of its proper divisors (94987002755).

5034311143153 is an equidigital number, since it uses as much as digits as its factorization.

5034311143153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 94987002754.

The product of its (nonzero) digits is 32400, while the sum is 34.

Adding to 5034311143153 its reverse (3513411134305), we get a palindrome (8547722277458).

The spelling of 5034311143153 in words is "five trillion, thirty-four billion, three hundred eleven million, one hundred forty-three thousand, one hundred fifty-three".