Base | Representation |
---|---|
bin | 100100101000010010001… |
… | …0101000011011111010001 |
3 | 122211021102210122011020022 |
4 | 1021100210111003133101 |
5 | 1124440232124420001 |
6 | 14412421451553225 |
7 | 1026500631615551 |
oct | 111204425033721 |
9 | 18737383564208 |
10 | 5034311170001 |
11 | 1671048458403 |
12 | 69382475b815 |
13 | 2a696c689b19 |
14 | 13593a5c5161 |
15 | 8ae49a8911b |
hex | 494245437d1 |
5034311170001 has 2 divisors, whose sum is σ = 5034311170002. Its totient is φ = 5034311170000.
The previous prime is 5034311169983. The next prime is 5034311170033. The reversal of 5034311170001 is 1000711134305.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3695775553600 + 1338535616401 = 1922440^2 + 1156951^2 .
It is a cyclic number.
It is not a de Polignac number, because 5034311170001 - 214 = 5034311153617 is a prime.
It is not a weakly prime, because it can be changed into another prime (5034311170081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2517155585000 + 2517155585001.
It is an arithmetic number, because the mean of its divisors is an integer number (2517155585001).
Almost surely, 25034311170001 is an apocalyptic number.
It is an amenable number.
5034311170001 is a deficient number, since it is larger than the sum of its proper divisors (1).
5034311170001 is an equidigital number, since it uses as much as digits as its factorization.
5034311170001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1260, while the sum is 26.
The spelling of 5034311170001 in words is "five trillion, thirty-four billion, three hundred eleven million, one hundred seventy thousand, one".
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