Base | Representation |
---|---|
bin | 100100101000010010001… |
… | …0101000011011110111111 |
3 | 122211021102210122011012122 |
4 | 1021100210111003132333 |
5 | 1124440232124414413 |
6 | 14412421451553155 |
7 | 1026500631615524 |
oct | 111204425033677 |
9 | 18737383564178 |
10 | 5034311169983 |
11 | 1671048458397 |
12 | 69382475b7bb |
13 | 2a696c689b04 |
14 | 13593a5c514b |
15 | 8ae49a89108 |
hex | 494245437bf |
5034311169983 has 2 divisors, whose sum is σ = 5034311169984. Its totient is φ = 5034311169982.
The previous prime is 5034311169973. The next prime is 5034311170001. The reversal of 5034311169983 is 3899611134305.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5034311169983 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5034311169973) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2517155584991 + 2517155584992.
It is an arithmetic number, because the mean of its divisors is an integer number (2517155584992).
Almost surely, 25034311169983 is an apocalyptic number.
5034311169983 is a deficient number, since it is larger than the sum of its proper divisors (1).
5034311169983 is an equidigital number, since it uses as much as digits as its factorization.
5034311169983 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2099520, while the sum is 53.
The spelling of 5034311169983 in words is "five trillion, thirty-four billion, three hundred eleven million, one hundred sixty-nine thousand, nine hundred eighty-three".
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