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5034311298353 is a prime number
BaseRepresentation
bin100100101000010010001…
…0101100010110100110001
3122211021102210212200022002
41021100210111202310301
51124440232143021403
614412421454423345
71026500632662011
oct111204425426461
918737383780262
105034311298353
111671048535887
12693824801b55
132a696c70337c
1413593a619c41
158ae49ab2188
hex49424562d31

5034311298353 has 2 divisors, whose sum is σ = 5034311298354. Its totient is φ = 5034311298352.

The previous prime is 5034311298349. The next prime is 5034311298371. The reversal of 5034311298353 is 3538921134305.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2703107556769 + 2331203741584 = 1644113^2 + 1526828^2 .

It is a cyclic number.

It is not a de Polignac number, because 5034311298353 - 22 = 5034311298349 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5034311298298 and 5034311298307.

It is not a weakly prime, because it can be changed into another prime (5034311298853) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2517155649176 + 2517155649177.

It is an arithmetic number, because the mean of its divisors is an integer number (2517155649177).

Almost surely, 25034311298353 is an apocalyptic number.

It is an amenable number.

5034311298353 is a deficient number, since it is larger than the sum of its proper divisors (1).

5034311298353 is an equidigital number, since it uses as much as digits as its factorization.

5034311298353 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1166400, while the sum is 47.

The spelling of 5034311298353 in words is "five trillion, thirty-four billion, three hundred eleven million, two hundred ninety-eight thousand, three hundred fifty-three".