5034311300402 has 4 divisors (see below), whose sum is σ = 7551466950606. Its totient is φ = 2517155650200.

The previous prime is 5034311300401. The next prime is 5034311300453. The reversal of 5034311300402 is 2040031134305.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 3802035914161 + 1232275386241 = 1949881^2 + 1110079^2 .

It is not an unprimeable number, because it can be changed into a prime (5034311300401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1258577825099 + ... + 1258577825102.

Almost surely, 2^{5034311300402} is an apocalyptic number.

5034311300402 is a deficient number, since it is larger than the sum of its proper divisors (2517155650204).

5034311300402 is a wasteful number, since it uses less digits than its factorization.

5034311300402 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2517155650203.

The product of its (nonzero) digits is 4320, while the sum is 26.

Adding to 5034311300402 its reverse (2040031134305), we get a palindrome (7074342434707).

The spelling of 5034311300402 in words is "five trillion, thirty-four billion, three hundred eleven million, three hundred thousand, four hundred two".