5034311300401 has 2 divisors, whose sum is σ = 5034311300402. Its totient is φ = 5034311300400.

The previous prime is 5034311300353. The next prime is 5034311300453. The reversal of 5034311300401 is 1040031134305.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3050608066801 + 1983703233600 = 1746599^2 + 1408440^2 .

It is a cyclic number.

It is not a de Polignac number, because 5034311300401 - 2¹¹ = 5034311298353 is a prime.

It is not a weakly prime, because it can be changed into another prime (5034311370401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2517155650200 + 2517155650201.

It is an arithmetic number, because the mean of its divisors is an integer number (2517155650201).

Almost surely, 2^{5034311300401} is an apocalyptic number.

It is an amenable number.

5034311300401 is a deficient number, since it is larger than the sum of its proper divisors (1).

5034311300401 is an equidigital number, since it uses as much as digits as its factorization.

5034311300401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2160, while the sum is 25.

Adding to 5034311300401 its reverse (1040031134305), we get a palindrome (6074342434706).

The spelling of 5034311300401 in words is "five trillion, thirty-four billion, three hundred eleven million, three hundred thousand, four hundred one".